java输入四个数字,奇数相加

测试通过,基本满足你题目要求,写得不太好importjava.util.*;importjava.util.regex.*;publicclasst10{publicstaticvoidmain(St

好似没有吧

//仅供参考#includeintmain(){intn,sum=0;while(scanf("%d",&n)==1&&n+1){if(n%2==0)printf("%d\n",n);elsesum+

double[]nums={10,30,30.12,30.34,44,0.2};for(inti=0;i<nums.length;i++){for(intj=i+1;j<nums.leng

publicstaticvoidmain(String[]arg){intk=0;intm=0;System.out.println("输入一个四位数");Scannerinput=newScanne

等下我在给你写public static void main(String[] args) {    &nbs

publicstaticvoidmain(String[]args){//TODOAuto-generatedmethodstubScannerinput=newScanner(System.

n+(n+1)+(n+2)+(n+...)+(n+m)=10001000>=n>1,0

importjava.util.Scanner;publicclassEncpryt{publicEncpryt(){Scannerscan=newScanner(System.in);System.

publicstaticvoidmain(String[]args){Scannerscan=newScanner(System.in);String[]str=scan.nextLine().spl

package zhidao;import java.util.InputMismatchException;import java.util.Scanner;publi

importjava.math.BigDecimal;importjava.util.Arrays;importjava.util.LinkedList;publicclassJiHe{static

public static void main(String[] args) {Scanner input = 

if(变量%2==0){return"偶数";}else{return"奇数";}

publicclassTest{publicstaticvoidmain(String[]arsg){inttemp=1000009;StringtempStr=1000009+"";//转换成字符串

添加一个“命令按钮控件”,将以下代码复制,运行即可OptionExplicitPrivateSubCommand1_Click()Dimnum1AsInteger,num2AsIntegerDimsu

给你提供一个思路,定义1,2,3,4,5,6,7,8,9,0,十,百,千,万的拼音,然后按照你的读法把输入的数字先判断是几位数,然后按照规则输出就可以了

任意四个连续正整数可以表示为：a,a+1,a+2,a+3则：a×（a+1）×（a+2）×（a+3）=[a×（a+3）+1]^2证明,左式展开整理=a^4+6a^3+11a^2+6a+1右式展开整理=a

importjava.util.*;publicclassMath{publicstaticvoidmain(Stringargs[]){inta,b;Scannersc=newScanner(Sys

importjava.uti.Scanner;publicclasstest{publicstaticvoidmain(String[]args){Scannerscanner=newScanner(