求值:(tan10°-根3)·con10° sin50°
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/17 21:05:38
原式=2sin50°+2sin80°cos10°(12cos10°+32sin10°)2cos5°=2sin50°+2sin80°cos10°cos(60°−10°)2cos5°=2(22sin50°
(sin50°(1+√3*tan10°)-cos20°)/(cos80°*√(1-cos20°))=(sin50°(1+√3*sin10°/cos10°)-cos20°)/(cos80°*√(1-co
Sin50度(1+根号3乘以tan10度)=sin50°(1+tan60°tan10°)=sin50°×(cos60°con10°+sin60°sin10°)/cos60°cos10°=sin50°×
注:题目似乎多乘了一个sin80°![2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)=[2sin50°+sin10°(1+√3tan10°)]*√2(cos10°)=√2
把40°和50°利用90°转化一个至于小括号里的就利用45°的值为1解决
=sin50*(根号3*sin10+cos10)/cos10+根号3*(1-tan10*tan50)+根号3*tan10*tan50=根号3+sin50*(1+根号3tan10)=根号3*(根号3*s
(sin50°(1+√3*tan10°)-cos20°)/(cos80°*√(1-cos20°))=(sin50°(1+√3*sin10°/cos10°)-cos20°)/(cos80°*√(1-co
解(1+√3tan10)cos40=(cos10/cos10+√3sin10/cos10)cos40=[(cos10+√3sin10)/cos10]cos40=[2sin(10+30)/cos10]c
原式的分子部分=2sin50°+cos10°+√3cos10°×[(sin10°)/(cos10°)]=2sin50°+cos10°+√3sin10°=2sin50°+2[(1/2)cos10°+(√
(tan10°-根号3)cos10°÷sin50°=(sin10°-根号3cos10°)÷sin50°=2(1/2sin10°-1/2根号3cos10°)÷sin50°=-2(sin60°cos10°
(tan10°-√3)×cos10°/sin50°=(sin10°/cos10°-√3)×cos10°/sin50°=(sin10°-√3cos10°)/sin50°=2(cos60°sin10°-s
cos40°(1+3tan10°)=sin50°(1+3tan10°)=sin50°(cos10°+3sin10°)cos10°=2sin50°sin(30°+10°)cos10°=2cos40°&n
cos40°+sin50°(1+3tan10°)sin70°1+sin50°=cos40°+sin50°(1+3sin10°cos10°)cos20°1+cos40°==cos40°+cos40°(2
∵tan10°-3=sin10°cos10°−3=sin10°−3cos10°cos10°=2sin(10°−60°)cos10°=−2sin50°cos10°∴(tan10°-3)•cos10°si
原式=2sin50°+cos10°+3sin10°cos35°cos40°+sin35°sin40°=2sin50°+2cos50°cos5°=22(22sin50°+22cos50°)cos5°=2
sin50度[1+(根号3)tan10度]=sin50(cos10+√3sin10)/cos10=sin50*2sin(10+30)/cos10=2sin50sin40/cos10=2sin50cos
[2sin50°+sin10°(1+√3tan10°)]√(2sin80°)=[2sin50+sin10(cos10+√3sin10)/cos10]√2sin80=[2sin50cos10+2sin1
2sin50°+sin80°(1+√3tan10°)]/(√2cos5°)=[2sin50°+cos10°(1+√3sin10°/cos10º)]/(√2cos5°)=[2sin50°+2(
sin50°(1+根号3tan10°)=sin50°(cos10°+根号3sin10°)/cos10°=sin50°*2(cos60°cos10°+sin60°sin10°)/cos10°=sin50
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