c语言输入一个两位数,将该数的个位数和十位数字分别显示的程序

voidmain(){intn=-1;while(n

很简单,用while#includevoidmain(){intn;intm;printf("输入一个数:");scanf("%d",&n);while(n>=1){m=n%10;

#include <stdio.h>void main(){    int n;   &

#include <stdio.h>int main(){\x09int n,i=0,j=0;\x09scanf("%d",&n)

#includeintmain(){inta,sum=0;scanf("%d",&a);while(a){sum+=a%10;a/=10;}printf("sum=%d\n",sum);return0

#includeintmain(){inta;inti;intresult=1;printf("请输入一个奇数\n");scanf("%d",&a);if(a%2==0)printf("这不是奇数\n

#includeintmain(){intm[10],i,j=0,k;longn;scanf("%ld",&n);k=n;while(k>0){k/=10;j++;}i=j;while(i--){m[

#includeusingnamespacestd;intmain(){intn;cin>>n;do{cout

代码：#include <stdio.h>int sum(int n){\x05int s = 0;\x05while(n>

#includevoidcount(inta){intn0,n1;n0=n1=0;//初始化if(a>1;}printf("0的个数:%d\n1的个数:%d\n",n0,n1);}voidmain()

只是三位数的话,下面的代码就可以了!#includeintmain(){intn;inta,b,c;scanf("%d",&n);a=n%10;b=n/10%10;c=n/100;printf("%d

请输入:100357111317192329313741434753596167717379838997Pressanykeytocontinue#include#includeintmain(){\

请输入:100357111317192329313741434753596167717379838997Pressanykeytocontinue#include#includeintmain(){

intmain(intargc,char*argv[]){inti=0,j,tmp;intarr[4]={0};scanf("%d",&j);printf("yourinputwas:%d\n\n",

#includevoidmain(){chara[100];inti,n,m=0;gets(a);i=strlen(a);if(a[0]=='-')printf("er\n");els

财富值!

是是偶数且不被3整除,还是不是偶数且不被3整除?

#include#includeintmain(){intn;intt,l=0;inti,j;printf("输入n:");scanf("%d",&n);t=n;while(t){

#includeintmain(void){inti;scanf("%d",&i);while(i!=0){if(i%2==0&&i%3!=0)printf("%d",&i);elseprintf("

#includemain(){inta,b;scanf("%d",&a);for(b=1;