作业帮a = a a 运算后 a 的值
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/01 04:08:14
#include#includevoidmain(){inta,n,sum=0,temp=0;printf("inputtheaandn:\n");scanf("%d%d",&a,&n);printf
DimaAsInteger,nAsInteger,iAsInteger,sAsDoublea=Val(InputBox("a=?"))n=Val(InputBox("n=?"))Ifa>0And
孩子,作业要自己做.可以写两层循环或者把aaaa写成一个函数,然后在加法程序里调用这个函数
vara,n,i,j:Integer;s:Int64;beginReadln(a,n);s:=0;if(a
#includevoidmain(){inta,n,count=1;longintsn=0,tn=0;printf("pleaseinputaandn\n");scanf("%d%d",&a,&n);
main(){inta,n,i,sum;scanf("%d%d",&a,&n);intsn[1000];sn[0]=a;sum=a;for(i=1;i
aa*bb+aa+bb+1=4aba²b²-2ab+1+a²+b²-2ab=0(ab-1)²+(a-b)²=0ab-1=0a-b=0a=b=
packageaddtest1;publicclassaddTest{publicstaticvoidmain(String[]args){inta=2;inttimes=6;intresult=0;
设共有n个数s=a+(10^1+1)*a+(10^2+10^1+1)*a+…+(10^n+10^(n-1)+…+10+1)*a=(10^n+2*10^(n-1)+…+(n-2)*10^2+(n-1)*
#include"stdio.h"main(){longa,i,p,s,N;printf("请输入a值:\n");scanf("%ld",&a);printf("请输入a小于等于:\n");scanf
aa+ab+bb=(a+b)²-ab=49-12=37aa+3ab+bb=(a+b)²+ab=49+12=61
a^2+b^2-4a-6b+13=0(a^2-4a+4)+(b^2-6b+9)=0(a-2)^2+(b-3)^2=0因为平方有非负性所以a-2=0,b-3=0所以a=2,b=3所以a^2+b^2=4+
(aa-bb)(aa-bb)-8(aa+bb)=(a+b)²(a-b)²-8a²-8b²=2²(a-b)²-8a²-8b²
#includevoidmain(){inta,i,k,sum,n,t=0;scanf("%d",&n);sum=0,i=1,k=2;do{t=t+k;sum=sum+t;k=k*10;i++;}wh
∵a=2，∴原式=2a-(a+a)2(a-a)(a+a)=2a-a2+a+2aaa2-a=22-4+2+424-2=22-3-22=-3．故答案为：-3．
又已知aa-a=aa-b-5则a-b=5原式=0.5(a-b)(a-b)=12.5
n[10^(i-1)]*a+s