已知m(-1,3)n(6,2)点p在x轴上且pm pn最小则p的坐标是

根据题意得：m-n=2,m-2n+3=3,解得：m=4,n=2,∴m+n+10=16,A=4；4m+6n-1=27,B=3,∴A-B=1,

(M-N/根号M-根号N)+(M+4N-4根号MN/根号M-2N)=(根号M+根号N)+(根号M-2根号N)=2根号M-根号N=2根号3/3-根号3/9=根号3/3

∵2n-m=5∴m+5=2n5（m+5)²+6n-3m-60=5×4n²+6n-3(m+5)-45=20n²+6n-6n-45=20n²-45明教为您解答,如若

a^2m+3n=a^2mxa^3n=(a^m)^2x(a^n)^2=4x9=36a^6n+3=(a^2n+1)^3=5x5x5=125(（x^2)y)^2n=(x^n)^4x(y^n)^2=16x9=

(1)6a(m-n)^2-8a^2(m-n)^3=2a(m-n)^2[3-4a(m-n)](2)m(m-n)-n(n-m)=12可得,m(m-n)+n(m-n)=(m+n)(m-n)=12,m^2-n

因为(m-1)^2+|3m-2n|=0所以(m-1)^2=0；|3m-2n|=0解得m=1,n=1.5带入下式解的得(4m^2-mn+6n^2)-2(m^2-3mn+5n^2)=0.5

自己的功课自己做

n/m=3/4m/(m+n)=1/[1+n/m]=4/7n/(m-n)=1/[m/n-1]=3m^2/(m^2-n^2)=1/[1-n^2/m^2]=16/7所以原式=9/7当然,你可以通分来算,也能

原式=[(√m)²-(√n)²]/(√m-√n)+(√m-2√n)²/(√m-2√n)=√m+√n+√m-2√n=2√m-√n当m=1/3n=1/27时,原式=2√（1/

由A=-N+M次根号M+N+10是M+N+10的算术平方根得：M-N=2由B=-2N+M+3次根号4M+6N-1的立方根求B-A的立方根得：M-2N+3=3解得：M=4,N=2则A=M-N次根号M+N

两种情况.1.m=nn/m+m/n=1+1=22.m≠nm,n是方程x^2-3x-1=0的两个不同实根m+n=3,mn=-1sy所以n/m+m/n=[(m+n)^2-2mn]/(mn)=-11

3n-2m-1=0得：3n-2m=11、6n-4m=2(3n-2m)=2x1=22、(m+n)-(3m-2n-7)=m+n-3m+2n+7=3n-2m+7=1+7=8

由-m+2n=-6得m-2n=6将m-2n=6,代入3(m-2n)²-5(m-2n)-1得3×6²-5×6-1=108-30-1=77

[(3m+2n)(3m-2n)-(m+2n)(5m-2n)]÷(1/3)m=[9m²-4n²-5m²+2mn-10mn+4n²]÷(1/3)m=[4m²

因为(m-1)²≥0|6m+3n|≥0而已知(m-1)²+|6m+3n|=0所以(m-1)²=0且|6m+3n|=0求得m=1,n=-2(4m²-mn-6n&#

9^n=2,3^(2n)=2,因为3^m=6,所以3^m/3^(2n)=3^(m-2n)=6/2=3所以m-2n=12^(2m-4n+1)=2^[2(m-2n)+1]=2^[2+1]=2^3=8还是[

m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=[m(m-n)+n(m+n)-n^2]/(m^2-n^2)=m^2/(m^2-n^2)=1/(1-(n/m)^2)=1/(1-(3/2)^2

已知m=5n,则原式=(5n/(5n+n))+(5n/(5n-n))-(n^2)/(((5n)^3)-n^2)=(5/6)+(5/4)-[1/(125n-1)]=(25/12)-[1/(125n-1)

根据原式可知：m-3n=1,且2m+n-15=1,将m-3n=1移项后为m=1+3n,将其代入2m+n-15=1中：2×(1+3n)+n-15=17n=14n=2m-3×2=1m=7

4^m=2^2m=68^n=2^3n=22^(2m-3n+1)=2^2m÷2^3n×2=6÷2×2=6