已知f(x)=2根号3sinxcosx-sin2x 1 2cos2x

f(x)=sinx(sinx+√3cosx)=(sinx)^2+根号3sinxcosx=(1-cos2x)/2+根号3/2sin2x=sin2x*cosπ/6-cos2xsinπ/6+1/2=sin(

已知:函数f(x)=2sinxcosx+2√3cos²x-√3求:(1)单调增区间和最小正周期；(2)当x∈[-π/4,π/4]时求最值.f(x)=2sinxcosx+2√3cos²

1）f(x)=a·b=-2sin^x+2√3sinxcosx=cos2x-1+√3sin2x=2sin(2x+π/6)-1,它的增区间由（2k-1/2)π

F(x)=m.n=2根号3sinxcosx+cos^2x-sin^2x=根号3sin2x+cos2x=2sin(2x+π/6)

f(x)=2cosx[1/2sinx+√3/2cosx]-√3sin^2(x)+sinxcosx=sinxcosx+√3cos^2(x)-√3sin^2(x)+sinxcosx=sin2x+√3cos

(1)f(x)=(1/2)sinx+(√3/2)cosx=sin(x+π/3)最小正周期=2π值域=[-1,1](2)f(A)=√3/2sin(A+π/3)=√3/2A+π/3=2π/3A=π/3a=

f(x)=向量m.向量nf(x)=2sin^2x+2√3sinxcosx.=1-cos2x+√3sin2x.∴f(x)=2sin(2x-π/6)+1.(1)函数f(x)的最小正周期T：T=2π/2,∴

1.f(x)=sinx/3cosx/3+根号3cos^2x/3=1/2sin2x/3+根号3/2(cos2x/3+1)=sin(2x/3+pi/3)+根号3/2对称中心的横坐标满足sin(2x/3+p

f(x)=sinx+根号3cosx=2*sin(x+pi/3)1.T=2pi2.x用x-pi/3代替:y=sinx单调增区间：【0,pi/2】

(1)f(x)=msinxcosx-2√3（sinx)^2+√3=（m/2)sin2x+√3cos2x,x=π/6是函数y=f(x)的零点,∴（m/2+1)√3/2=0,m=-2.∴f(x）=-sin

分析,f(x)=a*b-√3=2sinx*cosx+2√3sin²x-√3=sin(2x)-√3cos(2x)=2sin(2x-π/3)当,2kπ+π/2≦2x-π/3≦2kπ+3π/2∴k

f(x)=√2(sinx-cosx)=2*【sinxcos（-π/4）+cosxsin（-π/4）】=2sin（x-π/4）1）、f（x）的最小正周期为T=2π值域为【-2,2】2）、图像过点(α,6

f(x)=2(sinx*√3/2-cosx*1/2)=2(sinxcosπ/6-cosxsinπ/6)=2sin(x-π/6)、1/2表示2分之1=====sinx=4/5,题目应该有x∈〔-π/2,

1、f(x)=(√3/2)sin2x+(1/2)cos2x=sin(2x+π/6)周期T=2π/2=π当x∈【0,π/2】时,2x+π/6∈【π/6,7π/6】则sin(2x+π/6)∈【-1/2,1

1.f(x)=2[(1/2)sinx/2+(√3/2)cosx/2]f(x)=2sin(x/2+π/3).f(x)的最小正周期T=2π/(1/2)=4π.－－－即为所求.∵f(x)=sinx的递增区间

f(x)=sinx+根号3cosx=2sin(x+π/3),即最小正周期为2π得到的g(x)=2sin(x+π/3-π/3)=2sinx,即在(O,π/2】上单调递增,在【π/2,π）上单调递减

1、f(x)=sinx(sinx+√3cosx)=sin²x+√3sinxcosx=(1-cos2x)/2+(√3/2)sin2x=(√3/2)sin2x-(1/2)cos2x+1/2=si

f(x)=sinx/2+√3+cosx/2=sinx/2+cosx/2+√3=√2(√2/2sinx/2+√2/2cosx/2)+√3=√2(sin45°sinx/2+cos45°cosx/2)+√3

（1）、f(x)的定义域为sinx≠0,即x≠kπ；如果定义x=kπ时f(x)等于-1,可将定义域扩大至整个实数域；f(x)=[2√3sinxcosx-2cos²x]+1=√3sin2x-c