90÷x-90÷3x=3
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/18 20:48:37
1+(2x-4)/(x^2-a-2)]/[(x+3)/(x^2-1)]={1+2(x-2)/[(x-2)(x+1)]}(x^2-1)/(x+3)=[1+2/(x+1)](x+1)(x-1)/(x+3)
(56-X)=3(34-X)56-X=102-3X2X=46X=23
(x+1-1/1-x)÷(x-x²/x-1)=[(x+1)+1/(x-1)]×[-(x-1)/x(x-1)]=(x²-1+1)/(x-1)×(-1/x)=-x/(x-1)(x-4/
原式=(3x²+3x-x²+x)/(x+1)(x-1)*x(x²-1)/x²(x²-4)=(2x²+4x)/(x+1)(x-1)*(x+1)
x=1/x所以x=±1原式=(x+2)÷[(x+3)(x-3)/(x+3)]=(x+2)/(x-3)所以x=-1,原式=(-1+2)/(-1-3)=-1/4x=1,原式=(1+2)/(1-3)=-3/
解题思路:分式的混合运算,按照分式运算法则进行计算。解题过程:
1、y=[(x+3)²/(x+3)(x-3)]×[x(x-3)/(x+3)]-x+3=[(x+3)/(x-3)]×[x(x-3)/(x+3)]-x+3=x-x+3=3∴无论x取何值,y的值均
(x+2/x²-2x-x-1/x²-4x+4)÷x-4/x={(x+2)(x-2)/[x(x-2)²]-x(x-1)/[x(x-2)²]}·x/(x-4)={(
{[(x+2)/(x^2-2x)]-[(x-1)/(x-2)]}/[(x+3)/x]={[(x+2)/(x^2-2x)]-[(x^2-x)/(x^2-2x)]}*[x/(x+3)]=[(-x^2+2x
注意:本题x=2时题目没意义,应该舍去(这是很多学生错误所在)这里x只能取根号2-1
3x+x/3=180+306x+x=210*37x=630x=90
原式=2x(x-2)/(x+2)×x(x+2)/(x-2)²×3(x-2)/x=6x当x=√3/2时原式=3√3
x^3-2x^2+4x/x^2-4x+4÷x^2-2x+4/x-2=x(x²-2x+4)/(x-2)²÷(x-2)/(x²-2x+4)=x(x²-2x+4)/(
9x=90+4x9x-4x=905x=90x=18
2x-6/4-4x+x^2÷x-3/x-2=-2x-7/2+x-3/x=-x-3/x-7/2=1+3-7/21/2
|x|÷(x-3)+(3-x)÷x=0两边乘x(x-3)所以x|x|+(x-3)(3-x)=0若x>0|x|=xx²-x²+6x-9=0x=3/2若x
再答:采纳哟
=[3/(x+1)-(x-1)]÷(x²-2x)/(x+1)=[3/(x+1)-(x-1)(x+1)/(x+1)]÷x(x-2)/(x+1)=[3-(x+1)(x-1)]/(x+1)÷x(x
再答:不谢再答:求采纳再答:给个辛苦分
x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4)=x((2x-1)/x)+x/(x^2-2x)x(x^2-4)/(3-x)=(2x-1)+(x+2)/(3-x)=(7x-3-2x^2