分式2x^2 x-6分4x-5

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分式计算:x^5-4x^3+x+2/x^3+6x^2+12x+8(约分)

=[x^3(x+2)(x-2)+x+2]/[(x+2)^3]=[x^3(x-2)+1]/[(x+2)^2]没有什么明显的化简,检查一下题目是否正确

已知分式2x-1/x平方+2的值等于零,求分式-2x+4/x平方-5x+6的值

2x-1/x平方+2的值等于零∴2x-1=0x=1/2-2x+4/x平方-5x+6=-2(x-2)/(x-2)(x-3)=-2/(x-3)=-2/(1/2-3)=4/5

解分式方程6x-1/3x+2=4x-7/2x-5

Х=1再问:过程?再答:(6x-1)×(2x-5)=(4x-7)×(3x+2)然后拆开,简化最后就得答案了再问:能不能帮忙检验一下,我刚才检验一下,好像不等于1再答:把1带进去,就可以了再问:可代进去

分式计算x²+2x/x²-6x+9÷x²-4/x²-3x

x²+2x/x²-6x+9÷x²-4/x²-3x=x(x+2)/(x-3)^2*x(x-3)/(x+2)(x-2)=x^2/[(x-3)(x-2)]

解分式方程x/X-2-1-X^2/X^2-5X+6=2X/X-3

是X/(X-2)-(1-X^2)/(X^2-5X+6)=2X/(X-3)吗?首先因式分解(X^2-5X+6)=(X-2)(X-3),显然X不等于2且X不等于3,所以等式两边同乘以(X-2)(X-3)得

分式2x−6

当分母x-6≠0,即x≠6时,分式2x−6有意义;故答案是:x≠6.

分式计算难题1.若x^2-3x+1=0,求分式(2x^5-5x^4-x^3+x^2-6x)/(x^2+1)2.(4x^2

算得比较急,很可能算错.不过方法应该没大问题1.分子=2x^5-5x^4-x^3+x^2-6x=(x^2-3x+1)*(2x^3+x^2)-6x=-6x分子是用短除法算的分母=3x所以原式=-22.a

解分式方程:4/5x+x/(5x-25)=5/(x^2-5x)

4/5x+x/(5x-25)=5/(x^2-5x)(4x-20)/5x(x-5)+x^2/5x(x-5)=25/5x(x-5)4x-20+x^2=254x+x^2=45x^2+4x+2^2=45(x+

已知分式4x^2-1分之6x^2+x-2的值为0,则x^-1= 已知(x分之1)+(y分之1),=5 则x+y+3xy分

已知分式4x^2-1分之6x^2+x-2的值为0,则x^-1=∵分式4x^2-1分之6x^2+x-2的值为0∴6x²+x-2=04x²-1≠0(3x+2)(2x-1)=0∴3x+2

解分式方程:x-3/x-1-x-4/x-2=x-5/x-3-x-6

(x-3)(x-2)-(x-4)(x-1))/((x-1)(x-2))=((x-5)(x-4)-(x-6)(x-3))/((x-3)(x-4))2/((x-1)(x-2))=2/((x-3)(x-4)

解分式方程:(5x-96)/(x-19)+(x-8)/(x-9)=(4x-19)/(x-6)+(2x-21)/(x-8)

(5x-96)/(x-19)+(x-8)/(x-9)=(4x-19)/(x-6)+(2x-21)/(x-8)5-1/(x-19)+1+1/(x-9)=4+5/(x-6)+2-5/(x-8)即1/(x-

分式方程练习题解分式方程4xˆ3+10xˆ2+16x+1/2xˆ2+5x+7=6xG

题设是这样吧~因为你的式子实在是复杂了点你就仔细看看括号啦应该括号没有括错的(4x^3+10x^2+16x+1)/(2x^2+5x+7)=(6x^3+10x^2+5x-1)/(3x^2+5x+1)=>

分式(x^2-3x-4)/(x^2-5x-6),当x为何值时.分式无意义?还有分式等于0?

档分母=0时,无意义x^2-5x-6=0x=-1或6当分子=0,分母不等于0时,分时=0,首先要保证分式有意义x^2-3x-4x=-1或4取x=4(-1时,分式无意义)

解分式方程(5x-4)/(x-2)=(4x+10)/(3x-6)-1

(5x-4)/(x-2)=(4x+10)/3(x-2)-1两边乘3(x-2)3(5x-4)=4x+10-3(x-2)15x-12=4x+10-3x+615x-12=x+1614x=28x=2经检验,x

x-1\x-2+x-6\x-7=x-2\x-3+x-5\x-6 分式方程

X-1/X-2-(X-2)/(X-3)=(X-5)/(X-6)-(X-6)/(X-7)(X-1)(X-3)-(X-2)²/(X-2)(x-3)=(X-5)(X-7)-(X-6)²/

一道分式方程.X-2分之X-1减X-3分之X-2=X-5分之X-4减X-6分之X-5.

X=4原式=(X-1)/(X-2)-(X-2)/(X-3)=(X-4)/(X-5)-(X-5)/(X-6)左边通分=[X^2-4X+3-X^2+4X-4]/[(X-2)(X-3)]=-1/[(X-2)

分式计算:x²+2x/x²-6x+9÷x²-4/x²-3x

分式计算:[(x²+2x)/(x²-6x+9)]÷[(x²-4)/(x²-3x)]原式=[x(x+2)/(x-3)²]•[x(x-3)/(