(x 2)^2-(3x-1)^2-搜答案-拍题作业网

设(x²-1)/(x²+2x)=t则8t+3/t=118t²-11t+3=0(8t-3)(t-1)=0解得t=3/8或t=11.t=3/8(x²-1)/(x&#

原式=3x2-x3+x3-2x2+1=x2+1=3+1=4

(x²+1)²-4x(x²-1)=（x²-1）²-4x(x²-1)+4x²=（x²-1-2x）²（x^4-2x

后面的x²＋11x－708有误吧!再问：没有题目就这样能不能帮我再答：那我就试试：原式为：1/x2+x+1/x2+3x+2+1/x2+5x+6+1/x2+7x+12+1/x2+9x+20=5

so easy、、提示一下,望采纳

原式=(x²+3x+9)/(x-3)(x²+3x+9)-6x/x(x-3)(x+3)-(x-1)/2(x+3)=1/(x-3)-6/(x-3)(x+3)-(x-1)/2(x+3)=

1/(x²+3x+2)=[(x+2)-(x+1)]/(x+1)(x+2)=1/(x+1)-1/(x+2)同理1/(x²+5x+6)=1/(x+2)-1/(x+3)1/(x²

1/(x2-5x+6)-1/(4x-x2-3)-1/(3x-x2-2)=1/(x2-5x+6)+1/(x2-4x+3)+1/(x2-3x+2)=1/(x-2)(x-3)+1/(x-3)(x-1)+1/

原式可化为1/(x+1)(x-3)+2/(x-3)((x+2)+3/(x+1)(x+2)=0两边同乘以：(x+1)(x+2)(x-3)得：(x+2)+2(x+1)+3(x-3)=0(x≠-1,x≠-2

2x-(3x-1)+2(x2)

要过程吗?再问：要再答：

两边乘x(x+1)(x-1)2(x-1)+3(x+1)=4x2x-2+3x+3=4x5x+1=4xx=-1经检验,x=-1时分母x+1=0增根,舍去方程无解

原式=[x+2x(x-2)-x-1(x-2)2]÷x2-16x2+4x=[x2-4x(x-2)2-x2-xx(x-2)2]÷x2-16x2+4x=x-4x(x-2)2•x(x+4)(x+4)(x-4)

x²+x-1/(x²+x)=3/2两边同时乘以(x²+x)得：(x²+x)²-1=3(x²+x)/22(x²+x)²-3

5x²－3x－5＝0△＝3²－4×5×(－5)＝109x＝[﹣(﹣3)±√109]/5由原方程可得所求式子＝(x＋5)－1/(x＋5)所求式子＝(118±6√109)/25－25/

X+3X+9/X-27+6X/9X-X-X-1/6+2X=X-X+3X-X+2X+9/X-27+2/3-1/6=4X+9/X-27+(4-1)/6=4X+9/X-27+1/2=4X+9/X-(54-1

原式=2x2-1，当x=-3时，原式=2×（-3）2-1=17．

原式=5x²-x²-(4x-x²)+2(x²-3x)=4x²-4x+x²+2x²-6x=7x²-10x

原式=-2x2+3x-5x+2x2+1+x2=x2-2x+1．

(x+1)²-2(x²-1)+(x-1)²=(x+1)²-2(x+1)(x-1)+(x-1)²=[(x+1)-(x-1)]²=2²

你好x²+3x-1=0两边同除以xx+3-1/x=0x-1/x=-3两边平方得x²+1/x²-2=9x²+1/x²=11x²+1/x