作业帮(3÷x+1-x+1)÷x²+4x+4÷x+1化简
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/27 16:56:54
原式=[(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)]÷2(x-4)/(x^3-2x^2)=[(x+2)/(x^2-2x)-(x-1)/(x-2)²)]*[x²(
[2(x-1)^2+(x-1)^3]÷(1-x)=[2(1-x)^2-(1-x)^3]÷(1-x)=2(1-x)-(1-x)^2=1-x^2
(x+1-1/1-x)÷(x-x²/x-1)=[(x+1)+1/(x-1)]×[-(x-1)/x(x-1)]=(x²-1+1)/(x-1)×(-1/x)=-x/(x-1)(x-4/
=(x+1)(x-1)/(x+2)²×1/(x+1)×(x+2)(x+1)/(x-1)=(x+1/(x+2)
A={x|x^2-2x-3<3(1-x)}={x|x^2+x-6<0}={x|-3<x<2}B={x|9-x^2>6-2x}={x|x^2-2x-3<0}={x|-
原式=(3x²+3x-x²+x)/(x+1)(x-1)*x(x²-1)/x²(x²-4)=(2x²+4x)/(x+1)(x-1)*(x+1)
解题思路：分式的混合运算，按照分式运算法则进行计算。解题过程：
（x+2/x²-2x-x-1/x²-4x+4）÷x-4/x={(x+2)(x-2)/[x(x-2)²]-x(x-1)/[x(x-2)²]}·x/(x-4)={(
是不是[3/(x-1)-x-1]÷[(x-2)/(x²-2x+1)][3/(x-1)-x-1]÷[(x-2)/(x²-2x+1)]={[3-(x²-1)]/(x-1)}÷
注意：本题x=2时题目没意义,应该舍去（这是很多学生错误所在）这里x只能取根号2-1
先化简去掉中括号：(1-x+x-1/x)÷(1-1/x-1)再化简：(1-1/x)÷(-1/x)=(1-1/x)x(-x)=1-x
满意请采纳,谢谢!再问：������˼Ŷ�������ٷ�һ��ô��再问：лл再答：再问：̫лл��再问：�ӣ�c-lgx+cos²x��-lgxdx再问：�ܰ��������ô��再问：
原式=x(x²-2x+3-3)×2/x²=x²(x-2)×2/x²=2x-4
(3x-3/x²-1)÷(3x/x+1)-1/x-1=3（x-1）/[(x+1)(x-1)]÷[3x/(x+1)]-1/(x-1)=1/x-1/(x-1)=(x-1-x)/x(x-1)=-1
解1：原式=x(x-1)/(x+1)*(x+1)/x=x-1解2：原式=(x+3)^2/(x+3)(x-3)*(x-3)/(x+2)=(x+3)/(x-3)*(x-3)/(x+2)=(x+3)/(x+
=【3x(x+1)-x(x-1)]/(x+1)(x-1)×(x+1)(x-1)/x=(3x²+3x-x²+x)/x=4
原式化简：{（x-3)(x-2)/(x-3)(x-4)}²÷{(x+1)(x+2)/(x-4)(x+2)}²{(x-2)/(x-4)}²÷{(x+1)/(x-4)}
=[3/(x+1)-(x-1)]÷(x²-2x)/(x+1)=[3/(x+1)-(x-1)(x+1)/(x+1)]÷x(x-2)/(x+1)=[3-(x+1)(x-1)]/(x+1)÷x(x
(1+1/x)÷(2x-1+x²/x)=（1+x）/x÷(2x²-1-x²)/x=(1+x)÷（x²-1）=(1+x)÷(x+1)(x-1)=1/(x-1)2x
x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4)=x((2x-1)/x)+x/(x^2-2x)x(x^2-4)/(3-x)=(2x-1)+(x+2)/(3-x)=(7x-3-2x^2