如图,等腰三角形ABC和等腰三角形ADE中,AB=AC,AD=AE,∠CAB=∠EAD,试说明:△ACE≌ΔABD
如图,等腰三角形ABC和等腰三角形ADE中,AB=AC,AD=AE,∠CAB=∠EAD,试说明:△ACE≌ΔABD
在△ABC和△ADE中,AB=AC,AD=AE,∠CAB=∠EAD.试说明CE=BD.
如图,在△ABC和△ADE中,AC=AB,AE=AD,∠CAB=∠EAD.求证CE=BD
如图,在△ABC和△ADE中,AC=AB,AE=AD,∠CAB=∠EAD=90°
如图(1),△ABC和△ADE中,已知AB=AC,AD=AE,且∠CAB=∠EAD
如图,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE,求证:△ABD≌△ACE.
如图 △ABC和△ADE中,已知AB=AC,AD=AE且∠CAB=∠EAD,请说明BE=CD成立的理由
如图,在△ABC和△ADE中,AB=AC,AD=AE,若BD=CE,求证∠ABD=∠ACE
已知如图等腰三角形ABC与DEF AB=AC AD=AE 且∠CAB=∠EAD 求证CE=BD
如图,已知在△ABC与△ADE中,AB=AC,AD=AE,且∠BAC=∠DAE,试说明:△ABD≌△ACE
初二几何题:已知等腰三角形△abc和△ade,ab=ac,ad=ae,∠bac=∠ade=α求∠ace
如图,在△ABC和△ADE中,AC=AB,AE=AD,∠CAB=∠EAD=90°.求证CE=BD;CE⊥BD.