1.（3x-y)^2-3x+y

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/04/28 16:03:40

1.（3x-y)^2-3x+y
2.(2a+s)^2-6(2a+s)+9
3.4(x-y)^2+4(x-y)+1
4.(4x^2+1)^2-16x^2
5.(x-y)^3+2×(y-x)^2
6.4(3a+2x)^2-9(a-x)^2
7.y-x+3(x-y)^2

（3x-y)^2-3x+y=（3x-y)(3x-y-1)
(2a+s)^2-6(2a+s)+9=(2a+s-3)^2
4(x-y)^2+4(x-y)+1=(2x-2y+1)^2
(4x^2+1)^2-16x^2=(4x^2+1+4x)(4x^2+1-4x)=（2x+1)^2(2x-1)^2
(x-y)^3+2×(y-x)^2=(x-y)^2(x-y+2)
4(3a+2x)^2-9(a-x)^2=(6a+4x+3a-3x)(6a+4x-3a+3x)=(9a+x)(3a+7x)
y-x+3(x-y)^2 =(y-x)(1+2y-2x)

1.（（y+2x)(-2x+y)+4(x+2y)^2)/3y 2.（2(x-y)^3-8(x-y）^2(x+y)+6y( 1.（x+y-z)+(x-y+z)-(x-y-z) 2.2x-(3x-2y+3)-(5y-2) [(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y) 化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方【x-3y][x+y]-[x-2y][x +2y]-[x-y 有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【- 计算(x+y)(x+y)^2(-x-y)^3 数学(x-y)^5*(y-x)^3*(x-y)^2 已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) (x-y)^2-(x-y)^3因式分解计算:(-x-2y) * (3x-y)