已知4x-3y-6z=0,x+2y-7z=0,xyz≠0,求2x
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已知4x-3y-6z=0,x+2y-7z=0,xyz≠0,求
2x
4x-3y-6z=0 ①,
x+2y-7z=0 ②, ②×4,得4x+8y-28z=0③, ③-①,得11y-22z=0,即y=2z, 把y=2z代入②得,x+4z-7z=0,即x=3z, 把y=2z,x=3z代入,原式= 2(3z)2+3(2z)2+6z2 (3z)2+5(2z)2+7z2= 36z2 36z2=1.
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