| x=6-3y | x+3y-2xy+2z
x=6-3y ① x+3y-2xy+2z2=0 ②, 把①代入②中,可得: 6(y-1)2+2z2=0, 即y=1,z=0, 故x=3, 所以x2y+z=32=9, 故答案为9.
实数x、y、z满足x=6-3yx+3y-2xy+2z
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