(1+1/2002+1/2004+1/2006)X(1/2002+1/2004+1/2006+1/2008)X(1/20

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/05/24 06:34:32

(1+1/2002+1/2004+1/2006)X(1/2002+1/2004+1/2006+1/2008)X(1/2002+1/2004+1/2006)
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最后一个式子缺失1/2008
设1/2002+1/2004+1/2006=x
1/2002+1/2004+1/2006+1/2008=y
（1+1/2002+1/2004+1/2006）*（1/2002+1/2004+1/2006+1/2008）-（1+1/2002+1/2004+1/2006+1/2008）* (1/2002+1/2004+1/2006)
=(1+x)y-(1+y)x
=y+xy-x-xy
=y-x
=1/2008

x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002 若x^4+x^3+x^2+x+1=0,求x^2006+x^2005+x^2004+x^2003+^2002的值. 化简：1+x+x(1+x)+x(1+x)^2+……+x(1+x)^2006 已知x^2+x+1=0,求x^2004+x^2003+x^2002 1+x+x^2+...+x^2004+x^2005=0 求x^2006 已知1+x+x^2+.+x^2004+x^2005=0,则x^2006=_____ 已知x^2007=2,则（x^2006+x^2005+x^2004+...+x+1)(x-1)的值已知x^2007=2,则(x^2006+x^2005+x^2004+.+x+1)×(x-1)＝ x+1 x x x+1 计算1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3).+1/(x+2003)(x+2004) 化简：1/X(X+1) +1/(X+1)+(X+2) +1/(X+2)(X+3) +.+1/(X+2006)(X+200 1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...1/(x+2005)(x+2006)