若m-2m+10=6n-n 求【m-n/m+2mn+n+2/mn÷(1/m+1/n)】÷1/m+n 怎样做?
先化简(m/m-n-n/m+n+2mn/m²-n²)²÷m²+mn/m,若m=1
若m-n=4,mn=-1求(9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)
若m-n=4,mn=-1,求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值
若m-n=4,mn=-1,求(-2mn+m+n)-(3mn+5n-5m)-(m+4n-3mn)的值
1+n-m/m+2n÷m²-n²/m²+4mn+4n²=
m(m+n)(m-n)-m(m+n)的平方,其中m+n=1,mn=-1/2
mn(1/m-1/n)÷m^2-n^2/m+n
已知m-n=2,mn=1,求多项式(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值
已知m-n=3,mn=-1,求多项式-2mn+2m+3n-3mn-2n+2m-4n-m-mn的值
已知:m*m=n+2,n*n=m+2.求m*m*m-2mn+n*n*n(m不等于n).
1+n-m÷m²-n² --- ---- m+2n m²+4mn+4n²
数学题[(m+3n)(m-3n)+(2n-m^2)+5n^2(1-m)-(2m^2-m^2n)÷(-1/2mn)