2/1+(3/1+3/2)+(4/1+4/2+4/3)+(5/1+5/2+5/3+5/4)+...+(10/1+10/2
来源:学生作业帮 编辑:拍题作业网作业帮 分类:数学作业 时间:2024/05/14 05:50:30
2/1+(3/1+3/2)+(4/1+4/2+4/3)+(5/1+5/2+5/3+5/4)+...+(10/1+10/2+...+10/9)的值是多少
2/1+(3/1+3/2)+(4/1+4/2+4/3)+(5/1+5/2+5/3+5/4)+...+(10/1+10/2+...+10/9)
=10-2/1-3/1-4/1-5/1-6/1-7/1-8/1-9/1-10/1
=10-(2/1+3/1+6/1)-(4/1-5/1-8/1-10/1)-7/1-9/1
=9-40/27-63/16
=40/341-63/16
=2520/20843
再问: 对么??????????????????????????????????????????????????????????????????????????????????????????????????????????????????????我怀疑不对!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!2520/20843???????????????????、、、、
=10-2/1-3/1-4/1-5/1-6/1-7/1-8/1-9/1-10/1
=10-(2/1+3/1+6/1)-(4/1-5/1-8/1-10/1)-7/1-9/1
=9-40/27-63/16
=40/341-63/16
=2520/20843
再问: 对么??????????????????????????????????????????????????????????????????????????????????????????????????????????????????????我怀疑不对!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!2520/20843???????????????????、、、、
求1/2+(1/3+2/3)+(1/4+2/4+3/4)+(1/5+2/5+3/5+4/5)+……+(1/10+2/10
1/2+(1/3+2/3)+(1/4+2/4+3/4)+(1/5+2/5+3/5+4/5)+…+(1/10+2/10+…
1 2 3 4 5 =10
1/1*2*3+1/2*3*4+1/3*4*5+.+1/8*9*10
/1/3-1/2/+/1/4-1/3/+/1/5-1/4/+.+/1/10-1/9/
1/2+1/3+2/3+1/4+2/4+3/4+1/5+2/5+3/5+4/5+~+8/10+9/10=?是多少?请说明
1 2 3 4 5
.1,2,3,4,5,
因式分解:(5/1*4/1*3/1*2/1*1)^10*(5*4*3*2*1)^10
求行列式1 -1 3 1 // 4 -5 10 3 // 2 -4 5 2 // -3 2 -7 -1 的值.
(1)12^13(3^10*4^11) (2) (5^4*3^3-5^3*3^2+5^2*3)/15
2/5×(3/4+1/5)÷9/10