∫ tan(2x-5)dx=
∫ ( tan^2 x + tan^4 x )dx
求不定积分∫(tan^2x+tan^4x)dx
求不定积分 ∫ tan^2 x dx
∫dx/(1+√(1-x^2))=? ∫tan^4(x)dx=?
∫(tan^(5)(x)*sec^(4)(x))dx
∫(sin x 分之一)dx=?∫(tan x分之一)dx=?.cos x.
∫sec^4x dx ∫sec^2x tan^2x dx
微积分求解:∫tan^2 (1/2 x) dx
求不定积分∫tan(x/2)dx
∫tan^2xdx=∫(sec^2x-1)dx
∫cosx cos3x dx ∫tan^3t sect dt ∫(sec^2x)/4+tan^2 dx
求不定积分(1)dx/√x(1+√x)(2)dx/e^x+(e^-x)+2 (3)(tan^5x*sec^4x)dx