2x³y+2x²y²-12xy³=
2x+y=0,求4x²+2xy(x+y)+y³
x³y-2x²y²+xy³
已知x+y=2,xy=1/2,求x³y+2x²y²+xy³
先化简,再求值:{xy(x²-3y)+3xy²}(-2xy)+x³y²(2x-y
一.x-y=2,则x²-2xy+y²= 二.x-y=-1,xy=3,则x³y-2x
化简x-y分之x + x³-2x²y+xy²分之y³ ÷ y²-x
因式分解x的5次方y-x³y+2x²y-xy
[-xy/(x-y)²]²×(y²-xy/x)³
-x²y+2xy²-y³ 因式分解
多项式因式分解 1,(x-y)³-(x-y)²(x+y) 2,x(x²-xy)-(4x
先化简再求值,3xy²(xy+2y²-x²)+3x³y²,其中x=2,
-2y³+(3xy²-x²y)-2(xy²-y³)