若数列an满足:an+1=1−1an,a1=2,则a2009=( )
若数列{AN}满足A1=0.5,AN=1-1/(AN-1),N大于等于2,则A2009+A2010等于几
已知数列{an}满足a1=6,a2=8,an+1+an-1=an(n≥2),则a2009=
数列an满足a1=3/2,a(n+1)=an^2-an+1则m=1/a1+1/a2````1/a2009整数部分是
若数列{An}满足An+1=An^2,则称数列{An}为“平方递推数列”,已知数列{an}中,a1=9,点(an,an+
一道数学数列题已知数列{an}的首项a1=1/3,且满足1/a(n+1)=1/an+5,则a2009=
数列an满足a1=2,an+1=4an+9,则an=?
1 在数列an中,已知 a1=1,a2=5,an+2=a(n+1)-an (n∈N)则a2009是多少
数列{an}满足a1=2,an+1=−1an+1,则a2010等于( )
已知数列an满足条件a1=-2 a(n+1)=2an/(1-an) 则an=
已知数列{an}满足a1=2,an+1=2an/an+2,则an等于多少
一直数列{an}满足a1=0,an=(an-1 +4)/(2an-1) ,求 an
数列{an}满足a1=1 an+1=2n+1an/an+2n