数学--整式运算4(x-y+z)-2(x+y-z)-3(-x-y-z)
初中数学整式加减问题已知x-y=2,y+z=3,求多项式(x-y)²+(x+z)²-(y+z)&su
数学 多项式(x+y-z)(x-y+z)-(y+z-x)(z-x-y)公因式
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
(y-x)/(x+z-2y)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z
x,y,z正整数 x>y>z证明 x^2x +y^2y+z^2z>x^(y+z)*y^(x+z)*z^(x+y)
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
设x、y、z为整数,证明:x^4*(y-z)+y^4*(z-x)+z^4*(x-y)/(y+z)^2+(z+x)^2+(
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x-2z+y)(y+z-2x)+(x
(x+y-z)(x-y+z)=
x/2=y/3=z/5 x+3y-z/x-3y+z
(x-2y+z)(x+y-2z)分之(y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y)
x-2y=-9 3x-y+z=4 y-z=3 2x+3y-z=12 2z+x=47 x+y+z=6 这是七年级下册数学1