sin(π/4+θ)=4/5 sin2θ=?
已知sinθ=4/5,且sinθ+cosθ>1,sin2θ=
若sin(π/4+α)=sinθ+cosθ,2sin^2β=sin2θ,求证:sin2θ+2cos2β=3
证明:2sinθ+sin2θ=4sinθ×cos^2(θ/2)
证明恒等式4sinθcos²θ/2=2sinθ+sin2θ
4sinθcos²θ/2=2sinθ+sin2θ
4sinΘcos²(θ/2)=2sinΘ+sin2Θ
求证4sinθ(cosθ/2)^2=2sinθ+sin2θ
已知sin^4θ+cos^4θ=5/9,则sin2θ=?
已知sin^4θ+cos^4θ=5/9,求sin2θ的值
己知sin^4θ+cos^4θ=5/9,求sin2θ的值
已知sin^4θ +cos^4θ=5/9,求sin2θ 的值
已知sin∧4θ+cos∧4θ=5/9,求sin2θ