[3(x+ y)^3-5(x+ y)^2-2x-2y]÷(x
来源:学生作业帮 编辑:拍题作业网作业帮 分类:数学作业 时间:2024/04/28 16:25:16
[3(x+ y)^3-5(x+ y)^2-2x-2y]÷(x
还有一道,[(a+b)^3-2(a+b)^2+(a+b)]÷(a+b)
还有一道,[(a+b)^3-2(a+b)^2+(a+b)]÷(a+b)
[3(x+y)^3-5(x+y)^2-2x-2y]/(x+y)
=[3(x+y)^3-5(x+y)^2-(2x+2y)]/(x+y)
=[3(x+y)^3-5(x+y)^2-2(x+y)]/(x+y)
=3(x+y)^2-5(x+y)-2
=3(x^+2xy+y^2)-(5x+5y)-2
=3x^2+6xy+3y^2-5x-5y-2
[(a+b)^3-2(a+b)^2+(a+b)]/(a+b)
=(a+b)^2-2(a+b)+1
=a^2+2ab+b^2-2a-2b+1
同学,这两题性质其实是一样的哦〜下次遇到这种题目不要忘记方法哦!(话说这个答案也太长了吧〜)
=[3(x+y)^3-5(x+y)^2-(2x+2y)]/(x+y)
=[3(x+y)^3-5(x+y)^2-2(x+y)]/(x+y)
=3(x+y)^2-5(x+y)-2
=3(x^+2xy+y^2)-(5x+5y)-2
=3x^2+6xy+3y^2-5x-5y-2
[(a+b)^3-2(a+b)^2+(a+b)]/(a+b)
=(a+b)^2-2(a+b)+1
=a^2+2ab+b^2-2a-2b+1
同学,这两题性质其实是一样的哦〜下次遇到这种题目不要忘记方法哦!(话说这个答案也太长了吧〜)
数学(x-y)^5*(y-x)^3*(x-y)^2
[(x+2y)^2 -(x+y)(3x-y)-5y^2]÷2x
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
(2X-3y)-(5x-y)
有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【-
化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方
【x-3y][x+y]-[x-2y][x +2y]-[x-y
[(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y)
数学题……555{(3x+y)(3x-y)-(x-5y)(5x-y)-(x-2y)²÷(-4x),x=-2.y
[(x+2y)²-(x+y)(3x-y)-5y²]÷(2x),其中x,y满足x²+4x+y
先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y
[(x+2y)(x-2y)-(2x-y)^2+(3x-y))2x-5y)]/(-x)