数列﹛an﹜的前n项和为Sn,a1=1,an+1=2Sn(n
数列{an}的前n项和为Sn,a1=1,an+1=2Sn(n∈N*)
设数列an的前n项和为Sn,a1=1,an=(Sn/n)+2(n-1)(n∈N*) 求证:数列an为等差数列,
数列An的前n项和为Sn,已知A1=1,An+1=Sn*(n+2)/n,证明数列Sn/n是等比数列
数列{an}的前n项和为Sn,a1=1,an+1=2Sn (n∈正整数)
已知数列{an}a1=2前n项和为Sn 且满足Sn Sn-1=3an 求数列{an}的通项公式an
数列an的前n项和为Sn,a1=1,2Sn=(n+1)an(n为正自然数) 1.证明an=(n/(n
已知数列{an}的前n项和为Sn,a1=-23,Sn+1Sn=an-2(n≥2,n∈N)
已知数列 an前n项和为Sn,a1=1,Sn=2a(n+1),求Sn
已知数列an的前n项和为sn,且a1=1,an+1=1/2sn
已知数列{an}的前n项和为Sn,且a1=1,an+1=1/2Sn.
设数列an的前n项和为Sn,已知a1=1,Sn+1=4an+2
设数列{an}的前n项和为Sn,若a1=1,Sn=2an+Sn+(n∈N+),则a6=