x y m 为实数,且√(x-2m-y)+√(x-4) =√(x+y-6)+√(6-x-y),求2x+3y-m=?
实数x,y满足x^2+y^2-6x+5=0,且x+2y+m
若实数x,y满足不等式组{x+3y-3>=0 2x-y-3=0} 且x+y最大值为9 求m=?
若√3x+5y-2-m+√2x+3y-m=√199-x-y×√x-199+y,求m的值
√[3x+5y-2-m]+√[2x+3y-m]=√[x-199+y]*√[199-x-y] 求m的值
实数x y m满足根号x+2 +3x+y+m的绝对值=0 且y为负数 求m的取值范围
已知x^(3m)=2 y^(2m)=3 求(x^(2m))^3+(y^m)^6-(x^2*y)^3m * y^m
若x.y是实数,且m=x^2-4xy+6y^2-4x-4y,求m的最小值.
已知实数x,y,m满足根号x+2+|3x+y+m|=0,且y为负数,则m的取值范围是() a.m>6 b.m<6 c.m
已知集合M={(x,y)|x,y为实数,且x²/4-y²/9=1},N {(x,y)|x,y为实数,
已知X、Y满足2X-7Y=3M,X+2Y=4m+5,且X+Y=0,求M的值
已知x.y满足2x-y=3m,x+2y=4m+5,且x+y=0,求m的值
已知x,y满足2x-y=3m,x+2y=4m+5,且x+y=0,求m的值