如图正方形ABCD中,AC与BD交于点O,AF平分∠BAC交BD与于点E交BC于点F,求证:FC=2OE
已知,如图,正方形ABCD中,对角线AC与BD相交与点O,AF平分角BAC,分别交OB,BC于点E,F 求OE=1/2F
如图,在正方形ABCD中,对角线AC与BD交于点O,AE平分∠BAC交BC于E,交BO于F,求证:EC=2FO
如图,在正方形ABCD中,对角线AC与BD相较于点O,AE平分∠BAC交BC与E,交BO于F,求证EC=2FO
如图1,在正方形ABCD中,对角线AC与BD相交于点O,AF平分∠BAC,交于BD点F.
如图1,在正方形ABCD中,对角线AC与BD相交于点E,AF平分∠BAC,交BD于点F. (1)求证:EF+ AC=AB
如图,在正方形ABCD中,对角线AC与BD交于点O,AE平分∠BAC于E,交BO于F.求证:EC=2FO
已知:如图,在正方形ABCD中,对角线AC与BD相交于点E,AF平分∠BAC,交BD于点F.求证:EF+AE=AB
已知:如图,在正方形ABCD中,对角线AC与BD相交于点E,AF平分∠BAC,交BD于点F.求证;EF+AE=AB.
如图,在正方形ABCD中,对角线AC与BD相交于点O,角BAC的平分线AE交BD于点F,交BC于点E &nbs
(2010•高淳县一模)如图1,在正方形ABCD中,对角线AC与BD相交于点O,AF平分∠BAC,交BD于点F.
如图,在正方形ABCD中,对角线AC与BD相交于点E,AF平分∠BAC,交BD于点F.『本题图见附件』
正方形ABCD中,AC,BD交于点o,角DBC的平分饯交AC于E,交DC于F,证oE等于2分之一DF?