lg5+2lg3=1-lg2+lg3是怎么算出来的?
lg15=lg3+lg5=lg3+1-lg2,请问最后一步是怎么来的?
(lg3(lg2+lg5)/lg2lg5) *[ lg5(lg3+lg9)/lg3lg9]*lg2=(lg3+2lg3)
对数换地公式例如2lg3/3lg2×5lg2/lg3=10/3请问是怎么算出来的?
lg2/lg3+lg5/lg3
请问lg2.lg3.lg5=?
lg2=0.3010 lg3=0.4771 lg15 =lg3+lg5 =lg3+1-lg2 =1.7781 中lg3+
2lg5/lg2*2lg2/lg3*2lg3/lg5=多少,
(2lg5·2lg2·2lg3)/(lg5·lg2·lg3)=
lg2*lg3=?lg5/lg2=?
[lg3+1]*lg5+lg2*lg3 接下来该怎么做,并说明原因
(2lg5/lg2)*(2lg2/lg3)*(2lg3/lg5)求解,谢谢!
1/(1+log3 2)+1/(1+log2 3)=lg3/(lg2+lg3)+lg2/(lg2+lg3)=1解释一下这