2n+(an^2+2n+1)/(bn+1)的极限等于2 求a,b的值
若(an^2-bn+10)/(3n+2)的极限是2 求a、b的值
求数列极限lim=[(an^2+bn-1)/(4n^2-5n+1)]=1/b 求a b的值
讨论数列an^2+bn+2/n+1的极限
等差数列{an},{bn}的前n项和分别为An,Bn,切An/Bn=2n/3n+1,求lim(n→∞)an/bn
高二的极限运算题 lim(2an+4bn)=8,lim(6an-bn)=1,求lim(3an+bn)的值 n趋向于无穷大
设bn=(n-1)/(an-2),(n大于等于2),an=n^a-n+2,且b(n+1)+b(n+2)+...b(2n+
若lim(2n+(an^2-2n+1)/(bn+2))=1 求a/b的值
已知lim n→无穷 (an^2+bn+5)/(3n-2)=2,求a,b的值
a1=1,a(n+1)=(1+1/n)an+n+1/2^n,设bn=an/n求数列bn的通项公式
数列极限的题目已知lim(n趋向无穷大)(5n-根号(an^2-bn+c))=2,求a,b的值
求数列的第二小问已知数列an,bn满足a1=1,a2=2,b(n+1)=3bn,bn=a(n+1)-an &
数列{an}的前n项和Sn=2an-1(n≥1),数列{bn}满足b1=3,b(n+1)=an+bn,求数列{bn}的前