c语言 求数列第an a0=1 ,a1=1 an=2 * an-2 / an-1 + 2 要求用function 和 f

求数列的通项公式：a0=0,a1=1,an=2an-1+an-2 数列｛an},a1=1,an+1=2an-n^2+3n,求｛an｝. 数列{an}中,a1=35,an+1-an=2n-1,求an 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 数列an满足a1=2,an+1=an²求an 数列an中,a1=3,an+1=an/2an+1,则an=? 数列{an}.a0=1,an=a0+a1+.an-1(n大于等于1)则an等于多少.an=a0+a1+...+an-1 已知数列{an}满足a1=2,an=an+1再-2,求an和S10 已知数列an满足a1=1,1/an+1=根号1/an^2+2,an>0,求an 已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an 一直数列{an}满足a1=0,an=（an-1 +4）/(2an-1) ,求 an