若方程x+1x+2−xx−1=a(x+2)(x−1)
解方程:xx−2+ x−9x−7= x+1x−1+ x−8x−6
用换元法解方程2xx−1+x−1x=4
如果方程2xx+1−x+1x=mx
当a取何值时,方程x−1x−2−2−xx+1=2x+ax
解方程1/(xx+x)+1/(xx+3x+2)+1/(xx+5x+6)+1/(xx+7x+12)+1/(xx+9x+20
解分式方程1−xx−2+2=12−x,可知方程( )
若关于x的方程3/x+a/(x+1)=2/(xx+x)-3/(x+1)无解,求a的值?
已知x−1x+2−xx−1=m(x+2)(x−1)
解分式方程xx+1−x+1x=kx
若关于x的方程2kx−1−xx
先阅读下面解方程x−1x-1−xx+1=5x−52x+2的过程,然后回答后面的问题:
用换元法解方程2(x−1)x+3+6(x+3)x−1=7