如下 设递增数列{an}满足a1=1,4an+1=5an+√9an^2+16(n∈N+)
设数列{an}满足:a1=1,an+1=3an,n∈N+.
设数列{an}满足an+1/an=n+2/n+1,且a1=2
设数列{an},a1=3,an+1=3an-2(n∈N*)
设数列an满足a1=2 an+1-an=3-2^2n-1
已知数列{an}满足:a1=3,an+1=(3an-2)/an ,n∈N*.(Ⅰ)证明数列{(an-1)/an-2
数列{an}满足a1=1 an+1=2n+1an/an+2n
数列{an}满足a1=1,且an=an-1+3n-2,求an
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
设b>0,数列an满足a1=b,an=nban-1/an-1+n-1(n≥2)求数列an通向公式.
设b>0,数列an满足a1=b,an=nban-1/an-1+n-1(n≥2)求数列an通向公式
已知数列{an}满足a1=1,an+1=2an/(an+2)(n∈N+),则数列{an}的通项公式为
设数列{an}中,a1=2,an+1=an+n+1,则通项an=?