x³-5x²y²-xy-y³-()=2x³+y² 请问这题这
[-xy/(x-y)²]²×(y²-xy/x)³
x³y-2x²y²+xy³
2x+y=0,求4x²+2xy(x+y)+y³
因式分解x的5次方y-x³y+2x²y-xy
化简x-y分之x + x³-2x²y+xy²分之y³ ÷ y²-x
[x(x²y²-xy)-y(x²-x³y)]÷3x²y
因式分解:[x(x²y²-xy)-y(x²-x³y)]÷3x²y
计算:x²y-(2xy²-5x²y)+3xy²-y³
已知x+y=2,xy=1/2,求x³y+2x²y²+xy³
-2y³+(3xy²-x²y)-2(xy²-y³)
已知x+y=5,xy=3,x³+y³=(x+y)(x²-xy+y²),则1/x&
一.x-y=2,则x²-2xy+y²= 二.x-y=-1,xy=3,则x³y-2x