x=(t^2-2)\(t+1) y=(2t)\(t+1) 求dy\dx

x=t^2+t y=ln(1+t) 求dy/dx 设x=t+arctan t+1,y=t的立方+6t－2,求dy／dx x=2t+cost y=t+e^t 求dy/dx y=y(x)由参数方程x=2t/(1+t^);y=(1-t^2)/1+t^2确定,求dy/dx 设函数y=y(x)由x=1-e^t和y=t+e^-t确定,求dy/dx和d^2y/dx^2 y= ∫[0,x](t-1)^3(t-2)dt,dy/dx(x=0) 参数方程x=(t-1)e^t,y=1-t^4,求dy/dx 求由参数方程x=1-t^2 y=t-t^2确定的函数y=y(x)的导数dy/dx 设x=e^-t y=e^-2t 求dy/dx x=2t^2 +1 y= sint 求dy/dx是多少? 设x=t^2+cost,y=1-sint,求dy/dx 方程组 x=ln√1+t^2 y=arctant 求 dy/dx