计算:sin(-14π/3)+cos(-20π/3)+tan(-53π/6)
计算sin(-α-5π)*cos(α-2分之π)-tan(α-2分之3π)*tan(2π-α)
三角函数计算:若sinθ+cosθ=√2 则tan(θ+π/3)=?
cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2等于?.
sin(-21π/4) cos(-20π/3) tan(-19π/6)=
化简:[sin(π+α)*cos(π-α)*tan(π-α)]/[cos(π/2+α)*tan(3π/2-α)*tan(
数学角度计算cos(π/3)-sin^2(π/4)+1/3*tan^2 (π/3)*sin(3π/2)+cosπ=?注:
已知tan(π-a)=2,计算3sin^2(π+a)-2cos^2(π-a)+sin(2π-a)cos(π+a)
已知tanα/2=2,1.求tan(α+π/4)的值 2.(6sinα+cosα)/(3sinα-2cosα)的值
已知tanα/2=2求tan(α+π/4)的值(6sinα+cosα)/(3sinα-2cosα)的值
计算:sinπ/6+cosπ/6+tanπ/6+cotπ/6
1.已知cos(π/6-α)=1/3,求sin(2/3π-α) 2.求证tan^2α-sin^2α=tan^2α-sin
已知cos(π+α)=-1/2 计算sin(2π+α)-tan(α-3π)的值