x²-x-6/x-1≥0
已知函数f(x)=x²+x+1,x≥0;2x+1,x
已知两个函数f(x)={x²,x≥0,-x,x<0,g(x)={x分之1,x>0,-x,x≤0.
f x ={x(1-x)x≥0,x(1+x)x
3≤|8-x| |x+1|>2-x |x+3|7|x+1| x^2-6|x|+9>0 |x-1|+|x+2|≥5
1.x²-3x-18≤0 2.-x²+x≥3x+1
设f (x)={2x+1(x≥0),x²+4(x
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
(x²-7x+12)(x²+x+1)>0,
5/x²+x-1/x²-x=0
6x+(2x²-3x)-(x²-1)
(x+2)(x-3)(x-6)(x-1)=0
x²+3x-2=0,x²-6x-6=0,3x²-4x-1=0,3x²+10x+3