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先化简,再求值(1+1/x+2)÷x平方-9/2x+4,其中,x=4

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先化简,再求值(1+1/x+2)÷x平方-9/2x+4,其中,x=4
[1+1/(x+2)]÷(x²-9)/(2x+4)
=[(x+2)/(x+2)+1/(x+2)]×2(x+2)/[(x+3)(x-3)]
=(x+3)/(x+2)×2(x+2)/[(x+3)(x-3)]
=2/(x-3)
=2/(4-3)
=2/1
=2 再答: [2/(a-1)-1/(a+1)]×(a²-1) ={2(a+1)/[(a+1)(a-1)]-(a-1)/[(a+1)(a-1)]}×[(a+1)(a-1)] =(2a+2-a+1)/[(a+1)(a-1)]×[(a+1)(a-1)] =a+3 =√3-3+3 =√3