证明x→0 lim(2x-1)/ln(1+x)=∞
lim(x→0)ln(1-2x)/x
lim(x→0)(cosx)^(1/ln(1+x^2))
lim(x→0)ln(x^2+1)等于
lim(x→0)(ln(1+x^2)/(sec-cosx))
求极限lim Ln(1+x) /x > .< x→0
lim(x->0)ln(1+2x)/e^x-1
lim(x趋向0)ln(1+sin x)/x^2
lim(x趋于0)[ln(1+2x)]/x
已知f(x)=ln(1+x) 求lim(x→0) f(x)/x
lim(x→0) [ln(1+x+x^2)-ln(1-x+x^2)]/arcsinx tanx 怎么算
对数函数的极限 lim(x→0) [ln(1+x)-ln(1-x)]/x
lim(x趋近于0)[1/ln(x+根号1+x^2)-1/ln(1+x)]