cos(π/3-2x)怎样化等于sin(2x+π/6)
函数f(x)=根号3sinωx+cosωx(ω>0)怎样变为f(x)=2sin(ωx+π/6)
sin(2x+ π/3)乘cos(2x+π/3)等于
已知函数f(x)=cos(2x-π/3)+sin^2 x-cos^2 x
已知函数f(x)=cos(2x-π\3)+sin²x-cos²x
1)诺sin(π/6-x)=1/3,则cos(2π/3+2x)等于
已知f(x)=-1/2+sin(π/6-2x)+cos(2x-π/3)+cos平方x.
函数f(x)=cos2x+cos(x+π/3)+sin(x+π/6)+3sin^2x的最小值
求证 tan(2π-X)sin(-2π-X)cos(6π-X)/ sin(X+3π/2)*cos(X+3π/2)=-ta
已知函数f(x)=cos(π/6-2x)+cos(2x+π/6)+sin(2x+π/3)-sin(π/3-2x).
设函数f(x)=2+sin(3x+π/12)cos(x+π/6)+cos(3x+π/12)sin(x+π/6)
求化简数学公式哦[3sin^2(x/2)+cos^2(x/2)-4sin(x/2)cos(x/2)]/tan(π+x)化
化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π