lim(x→0)[tan(2x+x^3)/sin(x-x^2)] 和lim(x→0)[(x-sinx)/(x+sinx)

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/04/27 17:23:50

lim(x→0)[tan(2x+x^3)/sin(x-x^2)] 和lim(x→0)[(x-sinx)/(x+sinx)]的答案和解法
如果错了请教教我怎麽解和解的过程.

第一题利用等价无穷小法则
lim(x→0)[tan(2x+x^3)/sin(x-x^2)]
=lim(x→0)[(2x+x^3)/(x-x^2)]=0
第二题分子分母同时除以x
lim(x→0)[(x-sinx)/(x+sinx)]
=lim(x→0)[(1-（sinx/x))/(1+(sinx/x))]然后利用等价无穷小
=lim(x→0)[(1-1)/(1+1）]=0

求极限（（sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1 lim (x→0)x-sinx/x lim(x→0)(1-x^2-e^-x)/sinx 求lim(x→0)[(x^2sin1/x)/sinx] 1.lim x→0,(tanx-sinx)/(sin2x)^3 2.lim x→0,sin(x-1)tan(x-1)/2 lim(x→0)(x-sinx)/(x+sinx) lim(x→0) x-sinx/x+sinx的极限 lim x→0((x+ sinx)/tanx) lim(x→0)sinx/|x| lim x趋向0 x^2-sinx/x+sinx lim(x->0)x/(sinx)^2=? 1.lim x→0 3x/(sinx-x)