(x²-2y²-z²)-(-y²+3x²-z²)+(5x
已知方程组﹛x+4y-3z=0 4x-5y+2z=0 ,xyz≠0,求﹙3x²+2xy+z²﹚÷﹙x
{x²-(y-z)²分之x²-y²}÷{(x-y)²-z²分
已知有理数想x,y,z满足(x-4)²+3丨x+y-z丨=0,则,(5x+3y-3z﹚的2008次方的末尾数字
25(x-y)²-10(y-z)+1因式分解
x²+y²+z²-2x+4y-6z+14=0,则x+y+z=?求详解
(x-3y+2z)²=
x-y-z=0 {x+y-3z=4 2x-5y+7z=21 三元一次方程解
若2x+5y+4z=6,3x+y-7z=-4,那么x+y-z的值是多少?
若x-y=6,xy=-8,求代数式(x+y+z)²+(x-y-z)(x-y+z)-2·z(x+y)的值
已知x/2=y/3=z/5,且3x+4z-2y=40,求x、y、z的值﹔详解
已知有理数x,y,z,且|x-3|+2|y+1|+(2z+1)²=0,求x+y+z的相反数的倒数.
x²+2xy+y²-z² 用分组分解法因式分解