12x+24y=60 16*0.8x+27*0.8y=60

(x*x+y*y)(x*x+y*y)-(x*x+y*y)=12 求x*x+y*y等于多少 x,y,z分别代表三个不同的数,且X+X=x=y+y,y+y+y+y=z+z+z,x+y+y+z=60 ,那么Y+X+Z x+y=450;40%x+30=60%y 函数y=x^(60/x) {X+2Y/2+3X-Y/3=5{0.2(X+2Y)+0.8(3X-Y)=4 3(x+y)+2(x-y)=20 0.3x+0.6y=60 x=?y=? 已知实数x，y满足关系式5x+12y-60=0，则x 3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27 解方程组 x=3y-6 0.8(x+y)=x+y-13.6 x+y=127 0.5x+0.8y=83 求x和y 如果x和y成正比例,当x=16,y=0.8；如果x=10时,y是多少 2(x+y) 3x+3y=24 x+y/2x x y/2y= 1