2009*(1+1/2+1/3+……+1/2008)-[1+(1+1/2+)+(1+1/2+3/1)+……+1+1/2+
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2009*(1+1/2+1/3+……+1/2008)-[1+(1+1/2+)+(1+1/2+3/1)+……+1+1/2+1/3+……+1/2008)]
原式= 2009×(1+1/2+1/3+.+1/2008)-2008×1-(2008-1)×1/2-(2008-2) ×1/3.-(2008-2007)×1/2008
=(2009-2008)×1+(2009-2008+1)×1/2+(2009-2008+2)×1/3.+(2009-2008+2007)×1/2008
=1+2×1/2+3×1/3.2008×1/2008
=1+1+1.+1
=2008
望LZ采纳@@!
=(2009-2008)×1+(2009-2008+1)×1/2+(2009-2008+2)×1/3.+(2009-2008+2007)×1/2008
=1+2×1/2+3×1/3.2008×1/2008
=1+1+1.+1
=2008
望LZ采纳@@!
初中计算题,难(1-1/2-1/3-……-1/2008)*(1/2+1/3+1/4+……+1/2009)-(1-1/2-
(1-1/2^)(1-1/3^)……(1-1/2007^)(1-1/2008^)
(-1×1/2)+(-1/2×1/3)+(-1/3×1/4)+…+(-1/2008×1/2009)
(1/2+1/3+……+1/1997)(1+1/2+……+1/1996)-(1+1/2+……+1/1997)(1/2+1
1、(1/2+1/3+……1/1007)*(1+1/2+……1/2006)-(1+1/2+……+1/2007)*(1/2
计算:(2009/1-1)×(2008/1-1)×…×(3/1-1)×(2/1-1)等于多少?
1、求证:1/1^2+1/2^2+1/3^2+……+1/2008^2
(1/2008-1)(1/2007-1)(1/2006-1)…(1/3-1)(1/2-1)
(1/1+2)+(1/1+2+3)+(1/1+2+3+4)+………+(1/1+2+3+………+100)
(2011/1-1)(2010/1-1)(2009/1-1)…(3/1-1)(2/1-1)
计算:(1/2009-1)(1/2008-)(1/2007-1)……(1/3-1)(1/2-1)
计算:(1/2+1/3+……+1/2006)(1+1/2+1/3+……+1/2005)-