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用js正则匹配1234567890出1234 56 78 90 我写的是var re=/(\d{4})(\d{2})(\

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用js正则匹配1234567890出1234 56 78 90 我写的是var re=/(\d{4})(\d{2})(\d{2})(\d{2})/
求一个更简单的写法,
匹配1234567890输出1234 56 78 90?
alert('1234567890'.replace(/^(\d{4})(\d{2})(\d{2})(\d{2})$/, '$1 $2 $3 $4'));