为什么lim n趋向无穷 (5n^2-4n)/(3n^2+2n-1)等于5/3
高数 lim n趋向无穷 lim(3^(1/n)-1)ln(2+2^n)
求极限 lim 【(1+2+3+...+n)/(n+2)-n/2】趋向是无穷
微积分求极限 n趋向于无穷 (根号(n^4+n+1)-n^2)(3n+4) 为什么是1.5
求极限 lim(n->无穷)[(3n^2-2)/(3n^2+4)]^[n(n+1)]
lim(n->无穷)[(3n^2+cn+1)/(an^2+bn)-4n]=5
已知lim,n趋向无穷,[2n-根号下(4n^2+kn+3)]=1
求极限 n趋向无穷 2^n+1 + 3^n+1/2^n+3^n
1、lim((4^n-3^(n+1)))除以((2^(2n+1))+3^n) 当n 趋向于无穷 求极限
求极限:Lim(1+1/n-1/n^2)^n n趋向于正无穷
求极限 n趋向于无穷 lim((根号下n^2+1)/(n+1))^n
求极限lim(n趋向于无穷)(n+1)(根号下(n^2+1)-n)
证明n趋向无穷时,5n^2/(7n-n^2)的极限等于-5