作业帮(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16-1/256
来源：学生作业帮 编辑：拍题作业网作业帮 分类：数学作业 时间：2024/05/18 13:14:29
(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16-1/256)
(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16-1/256)
=(2x^2-1/2)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16-1/256)
=(4x^4-1/4)(4x^4+1/4)(16x^6+1/16)/(256x^16-1/256)
=(16x^6-1/16)(16x^6+1/16)/(256x^16-1/256)
=(256x^16-1/256)/(256x^16-1/256)
=1
=(2x^2-1/2)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16-1/256)
=(4x^4-1/4)(4x^4+1/4)(16x^6+1/16)/(256x^16-1/256)
=(16x^6-1/16)(16x^6+1/16)/(256x^16-1/256)
=(256x^16-1/256)/(256x^16-1/256)
=1
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