作业帮用因式分解法解出下列方程：
来源：学生作业帮 编辑：拍题作业网作业帮 分类：数学作业 时间：2024/05/01 10:46:49
用因式分解法解出下列方程：
(4x-1)(5x+7)=0
3x(x-1)＝2(1-x)
(x+1)^2-25=0
2(x-3)=x^2-9
(4x-1)(5x+7)=0
3x(x-1)＝2(1-x)
(x+1)^2-25=0
2(x-3)=x^2-9
(4x-1)(5x+7)=0
4x-1=0或5x+7=0
x=1/4或x=-7/5
3x(x-1)=2(1-x)
3x(x-1)-2(1-x)=0
3x(x-1)+2(x-1)=0
(x-1)(3x+2)=0
x=1或x=-2/3
(x+1)²-25=0
(x+1+5)(x+1-5)=0
(x+6)(x-4)=0
x=4或x=-6
2(x-3)=x²-9
2(x-3)-(x²-9)=0
2(x-3)-(x+3)(x-3)=0
(x-3)(2-x-3)=0
(x-3)(-x-1)=0
x=3或x=-1
4x-1=0或5x+7=0
x=1/4或x=-7/5
3x(x-1)=2(1-x)
3x(x-1)-2(1-x)=0
3x(x-1)+2(x-1)=0
(x-1)(3x+2)=0
x=1或x=-2/3
(x+1)²-25=0
(x+1+5)(x+1-5)=0
(x+6)(x-4)=0
x=4或x=-6
2(x-3)=x²-9
2(x-3)-(x²-9)=0
2(x-3)-(x+3)(x-3)=0
(x-3)(2-x-3)=0
(x-3)(-x-1)=0
x=3或x=-1