(1)2a²(3a²-5b) (2)(2/3ab²-2ab)1/2ab (3) (-4x&
计算:-10ab(3/2ab²-1/5a²b);(-2a)²(3ab²-5ab&
已知|a+1|+(a-b-2)²=0化简ab-[3a²b(4ab²+ab)-3a²
2a²b(-1/2a²b³+5ab²)-3a²b(-2/3ab)5ab
(a+b)²+|b-1∕3|=0 求(5a²b-2ab²-3ab)-(2ab+5a
已知(a-2)+(b+1)=0,求多项式3ab+ab-3ab+5ab+ab+2分之1ab
已知a+b=A,ab=A+2008,1-2(a+ab)+(ab-2b)=3A.求a+b和ab的值
3(-ab+2a)-(3a-b)+3ab
(1)2(a²-ab)-4(2a²-3ab)-2[a²-(2a²-ab+b
3a²(1/3ab²-b)-(2a²b²-3ab)(-3a)=?
已知/a+2/+{b+1/4}²=0,求(a²b-2ab)-(3ab²+4ab)的值.
若|a-b+3|+(2a+b)²=0,化简2ˆ3ab(2ab+1)-a²(-2ab)
计算(2A²+3AB+B²)-2分之1A²+3AB-B²