加减消元法解方程{6x-5y=-4,12x-5y=-10 {2x-3y=4,-5x-3y=2 {x+2y=6,3x+2y

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/04/29 22:27:12

加减消元法解方程
{6x-5y=-4,12x-5y=-10 {2x-3y=4,-5x-3y=2 {x+2y=6,3x+2y=10 {5x-4y=12,5x+4y=-8

6x-5y=-4 ① 12x-5y=-10 ②②-①得 6x=-6x=-1 ③③代入①得 6×(-1)-5y=-4-6-5y=-45y=4-65y=-2y=-2/5方程组的解是 x=-1 y=-2/52. 2x-3y=4 ①-5x-3y=2 ②①-②得 7x=2x=2/7 ③③代入①得 2×2/7-3y=44/7-3y=43y=4/7-43y=-24/7y=-8/7方程组的解是 x=2/7 y=-8/73. x+2y=6 ①3x+2y=10 ②　②-①得 2x=4x=2 ③③代入①得 2+2y=62y=6-22y=4y=2方程组的解是 x=2 y=24. 5x-4y=12 ①5x+4y=-8 ②①+②得 10x=4x=2/5②-①得 8y=-20y=-5/2方程组的解是 x=2/5 y=-5/2

x+y/2+x-y/3=6,4(x+y)-5(x-y)=2用加减消元法解方程组 6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5 3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) 解方程组：x+y/2+x-y/3=6 4(x+y)-5(x-y)=12 (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20 {(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20 4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 5x-3y=2,4y+2x=6用加减消元法解方程组{3x+2y=8 5x-4y=6 加减消元法.