已知lim(a根号下(n2+2n)-bn)=1,求实数a+b
lim(5n-根号(an^2+bn+c))=2,求实数a,b,c
已知a b 是常数 lim(a根号(2n^2+n+1) -bn))=1 则a+b=
lim[{根号(n^2+an)}-(bn+1)]=b,求a
1 lim[2n+1-根号(an^2+bn+1)]=2 求a b的值
数列极限的题目已知lim(n趋向无穷大)(5n-根号(an^2-bn+c))=2,求a,b的值
lim(n2+2n+2)/(n+1)-an)=b,求a,b
若lim[2n+(an^2+2n+1)/(bn+1)=1,则a+b
看清题,已知lim((n平方+1/n+1)-an-b)=1,求实数a,b的值.
已知lim|b(n+1)/bn|=r 证明:lim n次方根|bn|=r
已知lim n→无穷 (an^2+bn+5)/(3n-2)=2,求a,b的值
a,b为常数.lim(n->无穷)an^2+bn+2/2n-1=3 求a,b
简单高数极限题证lim n分之根号下(n^2+a^2) =1 要具体步骤,