计算:x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/04/29 13:51:23

x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2
=(x-2)(x-3)/(x-3)(x-1)+(x-3)(x-1)/(x-1)²-(x-4)(x+1)/(x+1)(x-1)
=(x-2)/(x-1)+(x-3)/(x-1)-(x-4)/(x-1)
=(x-2+x-3-x+4)/(x-1)
=(x-1)/(x-1)
=1

化简计算~1/(x2-5x+6) - 1/(4x-x2-3) - 1/(3x-x2-2) 5x2—[x2+(4x—x2)—2(x2—3x)] 1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=1/(x+4) (x2+3x+9)/(x2-27)+(6x)/(9x-x2)-(x-1)/(6+2x) 解分式方程:2/x2+5x+6 + 3/x2+x-6=4/x2-4 5x2+4-3x2-5x-2x2-5+6x．解方程2/x2+x+3/x2-x=4/x2-1 1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=4/21 (x2+1)2-4x(x2-1)因式分解 (x2-x)2+(x2+3x+2)2-4(x2+x+1)2因式分解解方程：1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x 3x2-[7x-（4x-3）-2x2] 因式分解:(x2+2x+4)(x2+2x-3)-8